buffer_check_dirty

函数名称：Returns if the page has dirty or writeback buffers. If all the buffers* are unlocked and clean then the PageDirty information is stale. If* any of the pages are locked, it is assumed they are locked for IO.

函数原型：void buffer_check_dirty_writeback(struct page *page, bool *dirty, bool *writeback)

返回类型：void

参数：

类型	参数	名称
struct page *	page
bool *	dirty
bool *	writeback

* dirty = false

* writeback = false

BUG_ON(!PageLocked(page))

如果非page_has_buffers(page)则返回

如果Only test-and-set exist for PG_writeback. The unconditional operators are* risky: they bypass page accounting.则 * writeback = true

101

head等于If we *know* page->private refers to buffer_heads (page)

102

bh等于head

103

循环

104

如果buffer_locked(bh)则 * writeback = true

107

如果buffer_dirty(bh)则 * dirty = true

110

bh等于 circular list of page's buffers

111

当bh不等于head 循环

源代码转换工具开放的插件接口	X
支持：c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现：逻辑报告代码生成和批量转换代码

函数逻辑报告