函数逻辑报告 | 
Source Code:fs\dcache.c | 
Create Date:2022-07-29 10:37:36 | 
| Last Modify:2020-03-18 10:27:32 | Copyright©Brick | 
| 首页 | 函数Tree | 
| 注解内核,赢得工具 | 下载SCCT | English | 
函数名称:是子目录
函数原型:bool is_subdir(struct dentry *new_dentry, struct dentry *old_dentry)
返回类型:bool
参数:
| 类型 | 参数 | 名称 | 
|---|---|---|
| struct dentry * | new_dentry | |
| struct dentry * | old_dentry | 
| 3072 | 如果new_dentry恒等于old_dentry则返回:true | 
| 3075 | 循环 | 
| 3083 | 如果d_ancestor - search for an ancestor*@p1: ancestor dentry*@p2: child dentry* Returns the ancestor dentry of p2 which is a child of p1, if p1 is* an ancestor of p2, else NULL.则result = true | 
| 3085 | 否则result = false | 
| 3088 | 当read_seqretry( & rename_lock, seq)循环 | 
| 3090 | 返回:result | 
| 名称 | 描述 | 
|---|---|
| copy_tree | |
| has_locked_children | |
| is_path_reachable | Return true if path is reachable from root* namespace_sem or mount_lock is held | 
| propagate_one | 
| 源代码转换工具 开放的插件接口  | X | 
|---|---|
| 支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码  |