函数逻辑报告 | 
Source Code:fs\namespace.c | 
Create Date:2022-07-29 10:39:39 | 
| Last Modify:2020-03-12 14:18:49 | Copyright©Brick | 
| 首页 | 函数Tree | 
| 注解内核,赢得工具 | 下载SCCT | English | 
函数名称:Check that there aren't references to earlier/same mount namespaces in the* specified subtree. Such references can act as pins for mount namespaces* that aren't checked by the mount-cycle checking code, thereby allowing* cycles to be made.
函数原型:static bool check_for_nsfs_mounts(struct mount *subtree)
返回类型:bool
参数:
| 类型 | 参数 | 名称 | 
|---|---|---|
| struct mount * | subtree | 
| 2585 | bool ret = false | 
| 2587 | lock_mount_hash() | 
| 2588 | 以p循环如果mnt_ns_loop( root of the mounted tree )则 | 
| 2590 | 转到:out | 
| 2592 | ret = true | 
| 2593 | out : | 
| 2594 | unlock_mount_hash() | 
| 2595 | 返回:ret | 
| 名称 | 描述 | 
|---|---|
| do_move_mount | 
| 源代码转换工具 开放的插件接口  | X | 
|---|---|
| 支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码  |