函数逻辑报告 | 
Source Code:include\linux\cred.h | 
Create Date:2022-07-27 06:42:28 | 
| Last Modify:2020-03-12 14:18:49 | Copyright©Brick | 
| 首页 | 函数Tree | 
| 注解内核,赢得工具 | 下载SCCT | English | 
函数名称:get_cred_rcu
函数原型:static inline const struct cred *get_cred_rcu(const struct cred *cred)
返回类型:struct cred
参数:
| 类型 | 参数 | 名称 | 
|---|---|---|
| const struct cred * | cred | 
| 259 | nonconst_cred等于cred | 
| 260 | 如果非cred则返回:NULL | 
| 264 | validate_creds(cred) | 
| 265 | Can we skip RCU deletion? 等于0 | 
| 266 | 返回:cred | 
| 名称 | 描述 | 
|---|---|
| get_task_cred | get_task_cred - Get another task's objective credentials*@task: The task to query* Get the objective credentials of a task, pinning them so that they can't go* away | 
| 源代码转换工具 开放的插件接口  | X | 
|---|---|
| 支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码  |