函数逻辑报告 | 
Source Code:include\linux\task_io_accounting_ops.h | 
Create Date:2022-07-27 09:54:43 | 
| Last Modify:2020-03-12 14:18:49 | Copyright©Brick | 
| 首页 | 函数Tree | 
| 注解内核,赢得工具 | 下载SCCT | English | 
函数名称:task_io_get_inblock
函数原型:static inline unsigned long task_io_get_inblock(const struct task_struct *p)
返回类型:unsigned long
参数:
| 类型 | 参数 | 名称 | 
|---|---|---|
| const struct task_struct * | p | 
| 65 | 返回:0 | 
| 名称 | 描述 | 
|---|---|
| __exit_signal | This function expects the tasklist_lock write-locked. | 
| wait_task_zombie | Handle sys_wait4 work for one task in state EXIT_ZOMBIE. We hold* read_lock(&tasklist_lock) on entry. If we return zero, we still hold* the lock and this task is uninteresting. If we return nonzero, we have | 
| accumulate_thread_rusage | It would make sense to put struct rusage in the task_struct,* except that would make the task_struct be *really big* | 
| 源代码转换工具 开放的插件接口  | X | 
|---|---|
| 支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码  |