函数逻辑报告 | 
Source Code:kernel\futex.c | 
Create Date:2022-07-27 11:53:56 | 
| Last Modify:2020-03-17 15:28:32 | Copyright©Brick | 
| 首页 | 函数Tree | 
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函数名称:Caller must hold a reference on @pi_state.
函数原型:static int wake_futex_pi(unsigned int __user *uaddr, unsigned int uval, struct futex_pi_state *pi_state)
返回类型:int
参数:
| 类型 | 参数 | 名称 | 
|---|---|---|
| unsigned int __user * | uaddr | |
| unsigned int | uval | |
| struct futex_pi_state * | pi_state | 
| 1556 | bool postunlock = false | 
| 1558 | ret等于0 | 
| 1561 | 如果WARN_ON_ONCE(!new_owner)则 | 
| 1571 | 转到:out_unlock | 
| 1581 | 如果此条件成立可能性小(为编译器优化)(should_fail_futex(true))则ret等于负EFAULT | 
| 1592 | 如果The rest of the robust-futex field is for the TID:按位与curval的值恒等于uval则ret等于负EAGAIN | 
| 1598 | 如果ret则转到:out_unlock | 
| 1608 | 删除链表项并重新初始化 | 
| 1613 | 添加链表项 | 
| 1617 | postunlock等于Futex variant, that since futex variants do not use the fast-path, can be* simple and will not need to retry. | 
| 1619 | out_unlock : | 
| 1620 | raw_spin_unlock_irq( & 保护自旋锁) | 
| 1625 | 返回:ret | 
| 名称 | 描述 | 
|---|---|
| futex_unlock_pi | Userspace attempted a TID -> 0 atomic transition, and failed.* This is the in-kernel slowpath: we look up the PI state (if any),* and do the rt-mutex unlock. | 
| 源代码转换工具 开放的插件接口  | X | 
|---|---|
| 支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码  |