函数逻辑报告 | 
Source Code:kernel\relay.c | 
Create Date:2022-07-27 12:51:33 | 
| Last Modify:2020-03-17 19:20:22 | Copyright©Brick | 
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函数名称:lay_create_buf - allocate and initialize a channel buffer*@chan: the relay channel* Returns channel buffer if successful, %NULL otherwise.
函数原型:static struct rchan_buf *relay_create_buf(struct rchan *chan)
返回类型:struct rchan_buf
参数:
| 类型 | 参数 | 名称 | 
|---|---|---|
| struct rchan * | chan | 
| 166 | 如果 number of sub-buffers per buffer 大于Maximum allocatable size 除*的长度则返回:NULL | 
| 170 | 如果非buf则返回:NULL | 
| 174 | 如果非padding counts per sub-buffer 则转到:free_buf | 
| 178 | 如果非start of channel buffer 则转到:free_buf | 
| 181 | associated channel 等于chan | 
| 182 | 对象增加引用 | 
| 183 | 返回:buf | 
| 185 | free_buf : | 
| 188 | 返回:NULL | 
| 名称 | 描述 | 
|---|---|
| relay_open_buf | lay_open_buf - create a new relay channel buffer* used by relay_open() and CPU hotplug. | 
| 源代码转换工具 开放的插件接口  | X | 
|---|---|
| 支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码  |