函数逻辑报告 | 
Source Code:kernel\resource.c | 
Create Date:2022-07-27 10:04:42 | 
| Last Modify:2022-05-22 11:14:39 | Copyright©Brick | 
| 首页 | 函数Tree | 
| 注解内核,赢得工具 | 下载SCCT | English | 
函数名称:Return the conflict entry if you can't request it
函数原型:static struct resource *__request_resource(struct resource *root, struct resource *new)
返回类型:struct resource
参数:
| 类型 | 参数 | 名称 | 
|---|---|---|
| struct resource * | root | |
| struct resource * | new | 
| 198 | 循环 | 
| 209 | 返回:tmp | 
| 名称 | 描述 | 
|---|---|
| request_resource_conflict | quest_resource_conflict - request and reserve an I/O or memory resource*@root: root resource descriptor*@new: resource descriptor desired by caller* Returns 0 for success, conflict resource on error. | 
| reallocate_resource | allocate_resource - allocate a slot in the resource tree given range & alignment | 
| allocate_resource | allocate_resource - allocate empty slot in the resource tree given range & alignment | 
| __insert_resource | Insert a resource into the resource tree. If successful, return NULL,* otherwise return the conflicting resource (compare to __request_resource()) | 
| __reserve_region_with_split | |
| __request_region | __request_region - create a new busy resource region*@parent: parent resource descriptor*@start: resource start address*@n: resource region size*@name: reserving caller's ID string*@flags: IO resource flags | 
| 源代码转换工具 开放的插件接口  | X | 
|---|---|
| 支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码  |