函数逻辑报告 | 
Source Code:kernel\sched\rt.c | 
Create Date:2022-07-27 10:39:43 | 
| Last Modify:2020-03-12 14:18:49 | Copyright©Brick | 
| 首页 | 函数Tree | 
| 注解内核,赢得工具 | 下载SCCT | English | 
函数名称:on_rt_rq
函数原型:static inline int on_rt_rq(struct sched_rt_entity *rt_se)
返回类型:int
参数:
| 类型 | 参数 | 名称 | 
|---|---|---|
| struct sched_rt_entity * | rt_se | 
| 437 | 返回:on_rq | 
| 名称 | 描述 | 
|---|---|
| dequeue_rt_stack | Because the prio of an upper entry depends on the lower* entries, we must remove entries top - down. | 
| requeue_rt_entity | Put task to the head or the end of the run list without the overhead of* dequeue followed by enqueue. | 
| put_prev_task_rt | 
| 源代码转换工具 开放的插件接口  | X | 
|---|---|
| 支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码  |