函数逻辑报告 |
Source Code:kernel\workqueue.c |
Create Date:2022-07-27 10:24:00 |
| Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
| 首页 | 函数Tree |
| 注解内核,赢得工具 | 下载SCCT | English |
函数名称：Can I start working? Called from busy but !running workers.
函数原型：static bool may_start_working(struct worker_pool *pool)
返回类型：bool
参数：
| 类型 | 参数 | 名称 |
|---|---|---|
| struct worker_pool * | pool |
| 783 | 返回:L: currently idle workers |
| 名称 | 描述 |
|---|---|
| need_to_create_worker | Do we need a new worker? Called from manager. |
| worker_thread |
| 源代码转换工具 开放的插件接口 | X |
|---|---|
| 支持：c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现：逻辑报告 代码生成和批量转换代码 |